If x, y, and z are sets that are members of themselves, and I form a set of these three sets, to represent this, I can write something like: p = {x, y, z}. I cannot write x = {x, y, z} as that would either amount to x being a member of itself with y and z not being members of themselves (consistent with above in red), or it would amount to x being a member of itself twice (which is contradictory as nothing can be a member of itself twice, or be itself twice), with y and z being members of themselves once. This shows the following:

You cannot have a set of ALL sets that are not members of themselves because it will result in at least one set not being included in the set. In other words, some set x will have to be included in x, but it can't.

You cannot have a set of ALL sets that are members of themselves because it will result in at least one set being a member of itself twice. In other words, some set x will have to

**not**be included in x, but it can't.

For a detailed solution to Russell's paradox:

http://philosophyneedsgods.com/2021/05/ ... -infinity/